If it's not what You are looking for type in the equation solver your own equation and let us solve it.
6x^2-18x-18=24
We move all terms to the left:
6x^2-18x-18-(24)=0
We add all the numbers together, and all the variables
6x^2-18x-42=0
a = 6; b = -18; c = -42;
Δ = b2-4ac
Δ = -182-4·6·(-42)
Δ = 1332
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1332}=\sqrt{36*37}=\sqrt{36}*\sqrt{37}=6\sqrt{37}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-6\sqrt{37}}{2*6}=\frac{18-6\sqrt{37}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+6\sqrt{37}}{2*6}=\frac{18+6\sqrt{37}}{12} $
| 3.3x=19.8 | | 28/18=n/36 | | -6+8k+3=5 | | -9(k-98)=-9 | | 19c+31=26c+-74 | | 0.4v=1 | | -3(2x-3)+5=20 | | 5(4s+3)=235 | | x=44+20-180 | | (8x-19)+(5x+38)=180 | | 5x-7=13;x=-4 | | 96-10.2m=3 | | 12y-4=9-y | | x^2=-49 | | 12=10+m/3 | | .90(2x)=1 | | 9(m+2)=m+40 | | 130=5-8m | | 34f–2f=8 | | 96-10.2m=65.4 | | 4.65x-8.5=5.4x-6.1 | | 10^(x+7)=6^(2x) | | y+9=-20 | | -0.3k=-17 | | -2x-10=14-7 | | -9(x+11)+10x=-75 | | x^2-6x-10=13 | | B=4a+8 | | 6=s−–2 | | 2(f+1.05)=9.82 | | –2s+10=–2s | | f(4+1)=2f(4)+1 |